Find approximate fidelity with an exponential function

Calculates for given start Fidelity and end Fidelity the within Fidelity for a given number of time points using an exponential function, where with the par.slope stretching and compression of the function can be influenced. Here the exponential function is derived as the reflection of the logarithm function on the straight line par.slope has to be greater than 0, near zero then the values are almost constant, the greater then the values are going against the linear line

Usage

find.Fidelity.exp(time.points, Fid.End, Fid.T1, par.slope = 1)

Arguments

time.points

number of time points

Fid.End

Fidelity at the end (final time point)

Fid.T1

Fidelity at the begin (starting time point)

par.slope

Slope for the logarithmic function has to be greater 0, the greater towards 1 the more linear is the function

Value

a matrix: first column with time points, second column corresponding Fidelity for the time points